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MrMoke · **It's Tricky, but only the first time. -** 04-12-2014, 06:50 PM

Ifs and Whiles require a Boolean response (true or false), so dragging in any logical test satisfies the start, even (1>1).
Dragging a numeric function like "distanceTo" into either side gives one numeric value, so A.distanceTo(B) > 1.
Use the down arrow on the opposite side, select math and change it to 1+1, so A.distanceTo(B) > ( 1 + 1).

Lastly, use the same technique to replace the ones with A.getWidth()/2 and B.getWidth()/2, so

while(A.distanceTo(B) > ( (A.getWidth()/2)+(B.getWidth()/2) )

Probably seems like a lot of work, but if you have a routine that's constantly checking one object's distance to a list or array of 20 others, it requires negligible additional coding. You just replace say "B" with a reference to a list item.

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MrMoke Senior Member Status: Offline Posts: 501 Join Date: Sep 2007 Location: Austin, Texas	It's Tricky, but only the first time. - 04-12-2014, 06:50 PM Ifs and Whiles require a Boolean response (true or false), so dragging in any logical test satisfies the start, even (1>1). Dragging a numeric function like "distanceTo" into either side gives one numeric value, so A.distanceTo(B) > 1. Use the down arrow on the opposite side, select math and change it to 1+1, so A.distanceTo(B) > ( 1 + 1). Lastly, use the same technique to replace the ones with A.getWidth()/2 and B.getWidth()/2, so while(A.distanceTo(B) > ( (A.getWidth()/2)+(B.getWidth()/2) ) Probably seems like a lot of work, but if you have a routine that's constantly checking one object's distance to a list or array of 20 others, it requires negligible additional coding. You just replace say "B" with a reference to a list item.